What is the formula for #(a+b)^3#? Precalculus The Binomial Theorem Powers of the Binomial 1 Answer Massimiliano · David Y. Feb 3, 2015 The answer is: #(a+b)^3=a^3+3a^2b+3ab^2+b^3#. It's easy to prove: #(a+b)^3=# #=(a+b)(a+b)(a+b)=# #=(a^2+ab+ab+b^2)(a+b)=# #=(a^2+2ab+b^2)(a+b)=# #=a^3+a^2b+2a^2b+2ab^2+ab^2+b^3=# #=a^3+3a^2b+3ab^2+b^3#. Answer link Related questions What is meant by a power of a binomial? How do I find the cube of #(2 x + 5)#? How do I find the cube of #(2b + 6x)#? How do I find the cube of #(4 x - 5b)#? How do I find #(3+i)^4#? What happens when you square a binomial? How do I find the square of a binomial? What is the formula for squaring a binomial? What is #(x+y)^2#? What is meant by cubing a binomial? See all questions in Powers of the Binomial Impact of this question 229402 views around the world You can reuse this answer Creative Commons License