How do solve #1/(x+2)>=1/3# algebraically?

1 Answer
Sep 12, 2016

Answer:

#x in (-2, 1].#.

Explanation:

If #x>-2, x+2 is positive, Cross multiplication would not change the

in-between inequality sign. So,

#x+2<=3 to x <=1#.

And so, #x in (-2, 1].

When #x<-2, x+2<0#. Now, cross multiplication reverses the

inequality sign. So,

#x+2>=3 to x>=1#. As #x<-2#, this is an extraneous solution..

It follows that the answer is , #x in(-2, 1]#.