How do you change the parametric equation to cartesian equation #x = t^2 - 1# and #y = t^3#?
1 Answer
Jan 14, 2017
Explanation:
You need to eliminate
In this case
# x=t^2-1 \ => t^6=(x+1)^3 #
#y=t^3 \ \ \ \ \ \ \ \ => t^6=y^2 #
And so:
# y^2 = (x+1)^3 #
Which you can multiply out if required.
