How do you compute the dot product for #<6, 1>*<-2, 3>#?
1 Answer
Oct 4, 2016
(6)(-2) + (1)(3) = -9
Explanation:
For any two vectors,
<
and
<
the dot is:
(6)(-2) + (1)(3) = -9
For any two vectors,
<
and
<
the dot is: