# How do you compute the dot product for #6j*4k#?

##### 1 Answer

Jul 1, 2016

0

#### Explanation:

#6j=0i+6j+0k=(0, 6 0) and 4k=0i+9j+4k=(0 0 4)

The dot product (a1 a2 a3).(b1 b2 b3)=((a1)(b1)+(a2)(b2)+(a3)(b3).

Here,

=(0 6 0).(0 0 4)

=(0)(0)+((6)(0)+(0)(4)