# How do you convert #-6 - 6i sqrt 3# to polar form?

##### 1 Answer

Jul 14, 2016

#### Explanation:

In polar form,

Comparing it with

we get

Squaring and adding 1 and 2,

Dividing equation 1 by 2

Real part of complex no =

Imaginary part of complex no =

At 3rd quadrant

Substituting the value in equation