# How do you convert # sqrt(3)+i# to polar form?

##### 2 Answers

Jun 23, 2016

I found:

#### Explanation:

Have a look:

Jun 23, 2016

#### Explanation:

To convert cartesian coordinates (x ,y) to Polar coordinates

#(r,theta)#

Use the formulae which link them.

#•r=sqrt(x^2+y^2)# and since

#sqrt3+i=(sqrt3,1)# is in the 1st quadrant , then.

#•theta=tan^-1(y/x)# here x =

#sqrt3" and "y=1#

#rArrr=sqrt((sqrt3)^2+1^2)=sqrt4=2# and

#theta=tan^-1(1/sqrt3)=pi/6" or "30^@#

#rArr(sqrt3,1)to(2,pi/6)#