How do you evaluate sin^-1(sin((-2pi)/3))?

1 Answer
Jun 4, 2016

$- \frac{2 \pi}{3}$.

Explanation:

If y = f(x) and the inverse relation is $x = {f}^{- 1} \left(y\right)$, then

$f \left({f}^{- 1} \left(y\right)\right) = y \mathmr{and} {f}^{- 1} \left(f \left(x\right)\right) = x$. The operands are returned as the values.

Here, the operand is $- \frac{2 \pi}{3}$, and so, the value is $- \frac{2 \pi}{3}$.

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