# How do you evaluate sin^-1(sin((7pi)/6))?

Jul 15, 2016

#(7pi)/6

#### Explanation:

The answer follows from the definition of the inverse ${f}^{- 1}$of a

function f:

If $y = f \left(x\right) , x = {f}^{- 1} \left(y\right) , {f}^{- 1} f \left(x\right) = x \mathmr{and} f {f}^{- 1} \left(y\right) = y$

Here, $f = \sin \mathmr{and} x = \frac{7 \pi}{6}$.