# How do you evaluate sin^-1(sqrt3/2)?

$\frac{\pi}{3} \mathmr{and} \frac{2 \pi}{3}$
${\sin}^{-} 1 \left(\frac{\sqrt{3}}{2}\right)$ --> $\arcsin \left(\frac{\sqrt{3}}{2}\right)$
$\sin x = \frac{\sqrt{3}}{2}$ --> there are 2 solutions:
arc $x = \frac{\pi}{3}$ and arc $x = \frac{2 \pi}{3}$