Question

How do you evaluate `tan(tan^-1(2/sqrt7))`?

Answer 1

`2/sqrt7`

Explanation:

`tan^-1 (2/(sqrt7)) -> arctan (2/sqrt7)` -> arc t (whose tan is (2/sqrt7))
There for:
`tan (tan^-1 tan (2/sqrt7))` --> `tan (t) = 2/sqrt7`