# How do you factor 15x^5-10x^4+5x^2 ?

Mar 2, 2017

$15 {x}^{5} - 10 {x}^{4} + 5 {x}^{2} = 5 {x}^{2} \left(3 {x}^{3} - 2 {x}^{2} + 1\right)$

#### Explanation:

In the polynomial $15 {x}^{5} - 10 {x}^{4} + 5 {x}^{2}$, we have three monomials

$15 {x}^{5}$, $- 10 {x}^{4}$ and $5 {x}^{2}$

As their GCF is $5 {x}^{2}$, we can take this common

and therefore, dividing each monomial by $5 {x}^{2}$, we get

$3 {x}^{3}$, $- 2 {x}^{2}$ and $1$.

Hence $15 {x}^{5} - 10 {x}^{4} + 5 {x}^{2} = 5 {x}^{2} \left(3 {x}^{3} - 2 {x}^{2} + 1\right)$