# How do you factor 3x^3 + 2x^2 - 27x - 18?

Jul 2, 2016

$3 {x}^{3} + 2 {x}^{2} - 27 x - 18 = \left(x + 3\right) \left(x - 3\right) \left(3 x + 2\right)$

#### Explanation:

$3 {x}^{3} + 2 {x}^{2} - 27 x - 18$

= ${x}^{2} \left(3 x + 2\right) - 9 \left(3 x + 2\right)$

= $\left({x}^{2} - 9\right) \left(3 x + 2\right)$

= $\left({x}^{2} - 3 x + 3 x - 9\right) \left(3 x + 2\right)$

= $\left(x \left(x - 3\right) + 3 \left(x - 3\right)\right) \left(3 x + 2\right)$

= $\left(x + 3\right) \left(x - 3\right) \left(3 x + 2\right)$