# How do you factor 6abc^(2) - 14a^(2)bc + 4ab^(2)c?

Jun 30, 2016

$2 a b c \left(3 c - 7 a + 2 b\right)$

#### Explanation:

Always look for a common factor first.
There is a common factor of $2 a b c$ which can be divided out of each term.

$6 a b {c}^{2} - 14 {a}^{2} b c + 4 a {b}^{2} c$

=$2 a b c \left(3 c - 7 a + 2 b\right)$