Question

How do you factor by grouping: `2x^3 + 8x^2 - 7x – 28`?

Answer 1

`(x+4)(2x^2-7)`

Explanation:

`2x^3+8^2-7x-28=0`

`2x^2(x+4)-7(x+4)=0`

`(x+4)(2x^2-7)=0`