# How do you factor completely n^2 + 7n - 44?

Jun 26, 2016

Find two numbers that multiply to $- 44$ and that add to $7$.

These two numbers are $11$ and $- 4$.

${n}^{2} + 7 n - 44 = \left(n + 11\right) \left(n - 4\right)$

Hopefully this helps!

Notice that $7 = 11 - 4$ hence

n^2+7n-44=n^2+(11-4)n-44=n^2-4n+11n-44= n(n-4)+11(n-4)=(n+11)(n-4)