How do you factor y=3x^3-300x y=3x3300x?

2 Answers
Dec 18, 2015

y = 3x(x^2 - 100)y=3x(x2100)

Explanation:

There is at least one xx on every term at the right so you can already factorize by xx, which gives you y = x(3x^2 + 300)y=x(3x2+300).

But 300 and 3 both have 3 as common divisor, so you can also say that y = 3x(x^2 - 100)y=3x(x2100). I hope that answers your question.

Dec 18, 2015

y=3x(x-10)(x+10)y=3x(x10)(x+10)

Explanation:

Factoring out 3x3x gives:

y=3x(x^2-100)y=3x(x2100)

But 100100 is 10^2102 giving:

y=3x(x^2-10^2)y=3x(x2102)

Known: (a^2-b^2)=(a-b)(a+b)(a2b2)=(ab)(a+b)

Applying this to our question gives:

y=3x(x-10)(x+10)y=3x(x10)(x+10)