How do you find the area given #a=3.05, b=0.75, c=2.45#?

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Answer 1 · 2017-03-04T17:06:31

Area of triangle is #0.613#

Given the three sides #a#, #b# and #c# of a triangle,

its area is given by #Delta=sqrt(s(s-a)(s-b)(s-c))#,

where #s=1/2(a+b+c)#.

Here as #a=3.05#, #b=0.75# and #c=2.45# and therefore

#s=1/2(3.05+0.75+2.45)=1/2xx6.25=3.125#

and #Delta=sqrt(3.125(3.125-3.05)(3.125-0.75)(3.125-2.45))#

= #sqrt(3.125xx0.075xx2.375xx0.675)#

= #=0.3757324=0.613#