# How do you find the area given a=3.05, b=0.75, c=2.45?

Mar 4, 2017

Area of triangle is $0.613$

#### Explanation:

Given the three sides $a$, $b$ and $c$ of a triangle,

its area is given by $\Delta = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$,

where $s = \frac{1}{2} \left(a + b + c\right)$.

Here as $a = 3.05$, $b = 0.75$ and $c = 2.45$ and therefore

$s = \frac{1}{2} \left(3.05 + 0.75 + 2.45\right) = \frac{1}{2} \times 6.25 = 3.125$

and $\Delta = \sqrt{3.125 \left(3.125 - 3.05\right) \left(3.125 - 0.75\right) \left(3.125 - 2.45\right)}$

= $\sqrt{3.125 \times 0.075 \times 2.375 \times 0.675}$

= $= 0.3757324 = 0.613$