How do you find the area of #triangle ABC# given b=3, c=9, sinA=1/4? Trigonometry Triangles and Vectors Area of a Triangle 1 Answer LM Dec 4, 2016 3.375 square units Explanation: #Area (triangle ABC) = 1/2 bc sin A# = #1/2 * 3 * 9 * 1/4# = #27/8# =#3 3/8# or #3.375# #A (triangle ABC#)= #3.375# square units Answer link Related questions How do you find the area of a triangle with 3 sides given? What is the area of a equilateral triangle with a side of 12? How do you find the area of a triangleABC, if #angleC = 62^@#, #b = 23.9# , and #a = 31.6#? How do you find the area of a triangleGHI, if #angleI = 15^@#, #g = 14.2# , and #h = 7.9#? What is Heron's formula? When do you use Heron's formula to find area? How do you find the area of a triangle ABC, if #a = 23#, #b = 46# , and #c = 41#? Question #f2e4c How do you find the area of the triangle given c= 4, A= 37 degrees, B= 69 degrees? How do you find the area of the triangle given C=85 degrees, a= 2, B= 19 degrees? See all questions in Area of a Triangle Impact of this question 1492 views around the world You can reuse this answer Creative Commons License