How do you find the derivative of sin^2 (2x+3)?

$\frac{d}{\mathrm{dx}} \left[{\sin}^{2} \left(2 x + 3\right)\right] = 4 \sin \left(2 x + 3\right) \cos \left(2 x + 3\right)$
$\frac{d}{\mathrm{dx}} \left[{\sin}^{2} \left(2 x + 3\right)\right] = 2 \sin \left(2 x + 3\right) \cdot \cos \left(2 x + 3\right) \cdot 2$