# How do you find the exact value of arcsin(sin(7*pi/3))?

$\arcsin \left(\sin \left(7 \cdot \frac{\pi}{3}\right)\right) = \frac{7 \pi}{3}$
As arcsin and sin are inverse ratios, hence $\arcsin \left(\sin \theta\right) = \theta$.
Hence, $\arcsin \left(\sin \left(7 \cdot \frac{\pi}{3}\right)\right) = \frac{7 \pi}{3}$.