# How do you find the exact value of cot^-1(-sqrt3)?

##### 1 Answer
Jun 11, 2017

${\cot}^{- 1} \left(- \sqrt{3}\right) = - \frac{\pi}{6}$

#### Explanation:

The range for ${\cot}^{- 1} x$ is from $- \frac{\pi}{2}$ to $\frac{\pi}{2}$

As $\cot \left(- \frac{\pi}{6}\right) = - \sqrt{3}$

${\cot}^{- 1} \left(- \sqrt{3}\right) = - \frac{\pi}{6}$