# How do you find the exact value of sin^-1(tan(-pi/4))?

##### 1 Answer
Sep 22, 2016

${\sin}^{- 1} \left(\tan \left(- \frac{\pi}{4}\right)\right) = - \frac{\pi}{2}$

#### Explanation:

As $\tan \left(- \frac{\pi}{4}\right) = - 1$ and $\sin \left(- \frac{\pi}{2}\right) = - 1$

${\sin}^{- 1} \left(\tan \left(- \frac{\pi}{4}\right)\right) = - \frac{\pi}{2}$