# How do you find the GCF of 4y, 18y^2, 6y^3?

Mar 31, 2017

See the solution process below:

#### Explanation:

The factors for each term are:

$4 y = \textcolor{red}{2} \cdot 2 \cdot \textcolor{red}{y}$

$18 {y}^{2} = \textcolor{red}{2} \cdot 3 \cdot 3 \cdot \textcolor{red}{y} \cdot y$

$6 {y}^{3} = \textcolor{red}{2} \cdot 3 \cdot \textcolor{red}{y} \cdot y \cdot y$

Therefore, the GCF for the three terms is: $\textcolor{red}{2 y}$