How do you find the GCF of #4y, 18y^2, 6y^3#?

1 Answer
Mar 31, 2017

Answer:

See the solution process below:

Explanation:

The factors for each term are:

#4y = color(red)(2) * 2 * color(red)(y)#

#18y^2 = color(red)(2) * 3 * 3 * color(red)(y) * y#

#6y^3 = color(red)(2) * 3 * color(red)(y) * y * y#

Therefore, the GCF for the three terms is: #color(red)(2y)#