Question

How do you find the indefinite integral of `int 1/(3x^2+3)dx`?

Answer 1

`int 1/(3x^2 + 3)dx = 1/3arctanx + C`

Explanation:

Factor out a `3` in the denominator.

`int 1/(3(x^2 + 1))`

`1/3int 1/(x^2 + 1)`

We now have a known integral.

`1/3arctanx + C`

Hopefully this helps!