# How do you find the indefinite integral of int (2sintheta+3costheta)?

##### 1 Answer
Mar 5, 2017

The answer is $= 3 \sin \theta - 2 \cos \theta + C$

#### Explanation:

We need

$\int \sin x \mathrm{dx} = - \cos x$

$\int \cos x \mathrm{dx} = \sin x$

Therefore,

$\int \left(2 \sin \theta + 3 \cos \theta\right) d \theta$

$= 2 \int \sin \theta d \theta + 3 \int \cos \theta d \theta$

$= - 2 \cos \theta + 3 \sin \theta + C$