How do you find the indefinite integral of #int -3 dx#?

2 Answers
Sep 4, 2016

Knowing that #intx^ndx=x^(n+1)/(n+1), n!=-1#,

#int-3dx=-3intx^0dx=-3*x^(0+1)/(0+1)=-3x+C#.

Sep 4, 2016

#-3/2x^2+c#

Explanation:

Use the #color(blue)"power rule for integration"#

#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1) x^(n+1))color(white)(a/a)|)))#

#rArrint(-3x)dx=(-3)/(2)x^2+c=-3/2x^2+c#

c- constant of integration.