How do you find the indefinite integral of #int (3x^-2-4x^-3)dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Sasha P. · mason m Sep 21, 2016 #-3/x + 2/x^2 + C# Explanation: #int (3x^-2-4x^-3)dx = 3intx^-2dx - 4intx^-3dx=# #=3 x^(-2+1)/(-2+1) -4 x^(-3+1)/(-3+1) + C = # #= 3 x^-1/-1 - 4 x^-2/-2 + C = -3/x + 2/x^2 + C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 8633 views around the world You can reuse this answer Creative Commons License
