How do you find the indefinite integral of #int -(5root3(x^2))/3dx#?

1 Answer
Feb 13, 2017

Rewrite the cube root as the #1/3# power and use the linear property of integration to move the constants outside the integral, then use the Power Rule

Explanation:

Rewrite the cube root as the #1/3# power and use the linear property of integration to move the constants outside the integral:

#int-(5root(3)(x^2))/3 = -5/3intx^(2/3)dx#

use the Power Rule for integrations, #intx^rdx = x^(r+1)/(r+1)+C#:

#-5/3intx^(2/3)dx = -5/3x^(5/3)/(5/3) + C#

#int-(5root(3)(x^2))/3 = -x^(5/3)+C#