# How do you find the integral of (7x^(3) -5) (2x^(2) +9) dx?

Apr 23, 2015

You can multiply the two brackets to get:
$\int \left(14 {x}^{5} + 63 {x}^{3} - 10 {x}^{2} - 45\right) \mathrm{dx} =$
and integrate, separating each term of your integral as a single integral (integral of a sum/difference is equal to the sum/difference of integrals) and using the fact that: $\int k {x}^{n} \mathrm{dx} = k {x}^{n + 1} / \left(n + 1\right) + c$ where $k$ is a constant and that $\int k \mathrm{dx} = k x + c$