# How do you find the integral ( x^4 - 3x^3 + 6x^2 - 7 ) dx?

May 20, 2015

Have a look:

hope it helps!

May 20, 2015

by definition, we know that $\int {x}^{n} \mathrm{dx} = \frac{{x}^{n + 1}}{n + 1}$

Thus,

$\int \left({x}^{4} - 3 {x}^{3} + 6 {x}^{2} - 7\right) \mathrm{dx} = \frac{{x}^{5}}{5} - \frac{3 {x}^{4}}{4} + 2 {x}^{3} - 7 x + c$