# How do you find the period of y=sin(x/3)?

##### 1 Answer
Nov 17, 2017

We have that the period of $\sin \left(x\right)$ is $2 \pi$. Thus, with a horizontal stretch of a factor of $3$, as given in the above equation, the period will become $2 \pi \cdot 3 = 6 \pi$.

Graphical confirmation:

graph{sin(x/3) [-10, 10, -5, 5]}

Hopefully this helps!