# How do you find the roots of .0625x^2=.125x+15 by factoring?

Feb 24, 2017

$x = 1 \pm \sqrt{241}$

#### Explanation:

$0.0625 {x}^{2} = 0.125 x + 15$

A good idea would be to remove the decimal coefficients. The smallest multiplicand which gives whole number coefficients is $16$, so we'll multiply the equation by $16$.

${x}^{2} = 2 x + 240$

${x}^{2} - 2 x - 240 = 0$

we can't factorise this equation so we're going to have to use the quadratic formula:

$x = \frac{2 \pm \sqrt{{2}^{2} - 4 \left(- 240\right) \left(1\right)}}{2} = 1 \pm \sqrt{241}$