How do you find the slope and intercept of #5y-4x+10=0#?

2 Answers
Apr 29, 2018

Answer:

#"slope "=4/5," y-intercept "=-2#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"rearrange "5y-4x+10=0" into this form"#

#"add 4x and subtract 10 from both sides"#

#rArr5y=4x-10#

#"divide all terms by 5"#

#rArry=4/5x-2larrcolor(blue)"in slope-intercept form"#

#"with slope "=4/5" and y-intercept "=-2#

Apr 29, 2018

Answer:

See below:

Explanation:

The equation of the line is

#5y-4x=-10#

#5y=4x -10#

So

#y= (4x)/5 - 10/5#

#y=4/5x-2#

This is in the form of

#y=mx+c#

where;

  • #y#-intercept #(c)=-2#
  • slope #(m)=4/5#

Hope this will help you :)