How do you find the slope and intercept of #(x+1)/2 + (y+1)/2 = 1#?

1 Answer
May 18, 2018

Answer:

Slope: #(-1)#
y-intercept: #0#

Explanation:

Given #(x+1)/2+(y+1)/2=1#

We can multiply everything (on both sides) by #2# to get an equivalent equation:
#color(white)("XXX")(x+1)+(y+1)=2#

Simplifying:
#color(white)("XXX")x+y+2=2#

#color(white)("XXX")y=-x#

or, in slope intercept form:
#color(white)("XXX")y=color(green)(""(-1))x+color(red)0#
with slope #=color(green)(""(_1))# and y-intercept #color(red)0#