# How do you find the slope and intercept of y = 2/3 x?

Mar 29, 2017

$m = \frac{2}{3} \mathmr{and} c = 0$

#### Explanation:

In order to identify the slope and y-intercept from an equation of a straight line, it is easiest if it is the form $y = m x + c$

We have that form here: $y = \frac{2}{3} x + 0$

The slope is the numerical co-efficient of the x-term and the y-intercept is given by the constant term

$y = \textcolor{red}{m} x + \textcolor{b l u e}{c}$

$y = \textcolor{red}{\frac{2}{3}} x + \textcolor{b l u e}{0}$

Therefore the slope, $\textcolor{red}{m = \frac{2}{3}}$

and the y-intercept is the point color(blue)((0,0)

Mar 29, 2017

$\text{slope "=2/3," y-intercept } = 0$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{slope-intercept form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = m x + b} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where m represents the slope and b, the y-intercept.

$y = \frac{2}{3} x \text{ is in this form as } y = \frac{2}{3} x + 0$

$\Rightarrow \text{slope "=m=2/3" and y-intercept } = b = 0$
graph{2/3x [-10, 10, -5, 5]}