# How do you find the slope of the secant lines of f(x) = -x^2 through the points: [-2, -4]?

Feb 8, 2018

$6$

#### Explanation:

$\text{the slope of the secant line is}$

•color(white)(x)(f(b)-f(a))/(b-a)

$f \left(b\right) = f \left(- 2\right) = - {\left(- 2\right)}^{2} = - 4$

$f \left(a\right) = f \left(- 4\right) = - {\left(- 4\right)}^{2} = - 16$

$\Rightarrow \frac{- 4 - \left(- 16\right)}{- 2 - \left(- 4\right)} = \frac{12}{2} = 6$