# How do you find the standard form of the equation for the parabola with vertex (4,0) and passing through the point (1,2)?

##### 1 Answer

Equation is

#### Explanation:

With vertex at

If it is regular type, if vertex is

equation is

or in standard form equation is

If parabola is horizontal, if vertex is

equation is

and in standard form equation is

graph{(4x+3y^2-16)(2(x-4)^2-9y)=0 [-10, 10, -5, 5]}