# How do you find the vertex and axis of symmetry for y = -3x^2 + 18x - 13?

Vertex of $y = - 3 {x}^{2} + 18 x - 13$
x-coordinate of vertex: $x = \left(- \frac{b}{2} a\right) = - \frac{18}{-} 6 = 3$