# How do you find the vertex and intercepts for #x =-1/2(y-2)^2-4#?

##### 1 Answer

(No 'Real Number' solution for y intercept)

#### Explanation:

Instead of an equation in

So instead the general shape being

Also the format of the given equation is in Vertex form.

'..................................................................

Then

'.......................................................................

But our equation is in

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Set

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Set

Add 4 to both sides

Multiply both sides by (-2)

Square root both sides

As you have square root of a negative number the graph does not cross the y axis.

So the only solution for the values of y are in the complex numbers set of values