# How do you find the vertex and intercepts for #y = 1/20x^2#?

##### 1 Answer

Jun 29, 2016

Vertex is at

y-intercept at

x-intercept (only one) at

#### Explanation:

One way to look at this is to considered the standard vertex form:

with vertex at

the given equation:

with vertex at

The y-intercept is the value of

The x-intercept(s) is(are) the value(s) of