How do you find the vertex and the intercepts for #F(x)=x^2-4x-7#?
Vertex is (2,
The equation has the form
This represents the parabola with vertex at (2,
The axis of the parabola is the line x = 2, from the vertex in the positive direction of the y-axis.
To get intercept on the x-axis, put y = 0 in the equation and find x.
For the y-intercept put xo 0.,