Question

How do you find the vertex of `f(x)=2x²+16x+33`?

Answer 1

Vertex (-4, 1)

Explanation:

`f(x) = 2x^2 + 16x + 33`
x-coordinate of vertex:
`x = -b/(2a) = -16/4 = - 4`
y-coordinate of vertex:
`f(-4) = 32 - 64 + 33 = 1`

Vertex (-4, 1)