# How do you find the vertex of the parabola y = (1/8)(x – 5)^2 - 3?

Apr 15, 2018

vertex: $\left(5 , - 3\right)$

#### Explanation:

it is in vertex form, so any number with x in the parenthesis is the shift in x-axis(if x+5 -->shift 5 to left, if x-5--> shift 5 to right).
and the single number at the end of the equation is the up and down of the y-axis( -3 down 3, 3 up 3). the $\left(\frac{1}{8}\right)$ is the stretch.

Apr 15, 2018

The vertex is $\left(5 , - 3\right)$.

#### Explanation:

$y = \frac{1}{8} {\left(x - 5\right)}^{2} - 3$ is a quadratic equation in vertex form:

$y = a {\left(x - h\right)}^{2} + k$,

where:

$\left(h , k\right)$ is the vertex.

$h = 5$, and $k = - 3$,

therefore the vertex is $\left(5 , - 3\right)$.