# How do you find the vertex of the quadratic equation y = –4(x + 6)^2 + 2?

Jan 28, 2016

The vertex is $\left(- 6 , 2\right)$.

#### Explanation:

$y = - 4 {\left(x + 6\right)}^{2} + 2$ is the vertex form for a parabola, $y = a {\left(x - h\right)}^{2} + k$, where $a = - 4 , h = - 6 , k = 2$.

The vertex of a parabola is the minimum or maximum point of a parabola. Since $a < 0$, the parabola opens downward and the vertex is the maximum point. The vertex of a parabola represented by the vertex form is $\left(h , k\right)$.

Therefore, the vertex for this parabola is $\left(- 6 , 2\right)$.

graph{y=-4(x+6)^2+2 [-10, 10, -2.12, 7.88]}