# How do you find the vertex of y=2x^2 +11x-6?

So, the solution set - or vertex set - is $\left(- \frac{11}{4} , - \frac{169}{8}\right)$
The x of the vertex($x - v e r t e x$) is found using the formula:
$\text{x-vertex} = - \frac{b}{2 a}$, in this case: $\text{x-vertex} = - \frac{11}{4}$.
The y of the vertex($y - v e r t e x$) is found using the formula:
$\text{y-vertex} = - \frac{\triangle}{4 a} = - \frac{{b}^{2} - 4 a c}{4 a}$, in this case: "y-vertex" = - [121 - (4 " x " 2" x"-6)] / (4 " x "2) =- 169/8 .
So, the solution set - or vertex set - is $\left(- \frac{11}{4} , - \frac{169}{8}\right)$