# How do you find the vertex of  y=2x^2-4x-2?

This is equation of a Parabola , the general form of which is $a {x}^{2} + b x + c$ . So here  a=2 ; b=-4 ; c=-2 Let the Co-ordinate of Vertex be ${x}_{1} , {y}_{1}$ . Now we know ${x}_{1} = - \frac{b}{2 \cdot a}$
$\therefore$ ${x}_{1} = \frac{4}{4} = 1$ Now plugging in ${x}_{1}$ in the equation we get ${y}_{1} = 2 \cdot 1 - 4 \cdot 1 - 2$ or ${y}_{1} = - 4$ So The Co-Ordinate of Vertex