# How do you find the vertex of y=x^2+2x-3?

vertex form of parabola is given as, $y = a {\left(x - h\right)}^{2} + k$ where, $\left(h , k\right)$ is the coordinate of vertex
Now givn equation is $y = {x}^{2} + 2 x - 3 = {x}^{2} + 2 x + 1 - 4 = {\left(x + 1\right)}^{2} - 4 = {\left(x - \left(- 1\right)\right)}^{2} + \left(- 4\right)$
So,coordinate of vertex is $\left(- 1 , - 4\right)$