How do you find the vertex of #y= x^2-8x+5#?
The simplest method for finding the vertex of the given polynomial is to convert it into "vertex form" to find the vertex at
If we can convert this into vertex form:
then the vertex will be at
The easiest way to do this conversion is via a "completion of the square method"
then the third term needs to be
So we add (and then subtract
So the vertex is at