Question

How do you find two missing sides of a Right Triangle with a right angle and a 50 degree angle and the hypotenuse is 2sqrt2?

Answer 1

Try this:

Using trigonometry:
`b=2sqrt(2)sin(50°)=2.16`
`a=2sqrt(2)cos(50°)=1.82`

Answer 2

If C = 90 deg, A = 50, and c = 2sqr2, we have these relations:

`b = 2sqr2.(cos 50) = 2(1.414)(0.65) = 1.81`

`a = 2sqr2.(sin 50) = 2(1,414)(0.766) = 2.17`